20y^2+41y-9=0

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Solution for 20y^2+41y-9=0 equation:


Simplifying
20y2 + 41y + -9 = 0

Reorder the terms:
-9 + 41y + 20y2 = 0

Solving
-9 + 41y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-9 + -4y)(1 + -5y) = 0

Subproblem 1

Set the factor '(-9 + -4y)' equal to zero and attempt to solve: Simplifying -9 + -4y = 0 Solving -9 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + -4y = 0 + 9 Combine like terms: -9 + 9 = 0 0 + -4y = 0 + 9 -4y = 0 + 9 Combine like terms: 0 + 9 = 9 -4y = 9 Divide each side by '-4'. y = -2.25 Simplifying y = -2.25

Subproblem 2

Set the factor '(1 + -5y)' equal to zero and attempt to solve: Simplifying 1 + -5y = 0 Solving 1 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5y = 0 + -1 -5y = 0 + -1 Combine like terms: 0 + -1 = -1 -5y = -1 Divide each side by '-5'. y = 0.2 Simplifying y = 0.2

Solution

y = {-2.25, 0.2}

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